GPS坐标转火星坐标

无聊写了个应用叫做Find my car，但是获取到的坐标一个是标准的gps坐标，另外一个就是上面的图吧的坐标。但是这个坐标直接在高德地图上标记却是错误的，于是就想办法看怎么转换下，不错这里直接有份源代码可以参考：猛击此处下载

这个项目引入了很多自定义的sqlite3的文件，其实没什么必要，改写一下就ok了。

#import <sqlite3 .h>
 
#define DBNAME @"gps.db"
//转换gps坐标为火星坐标
-(CLLocationCoordinate2D)zzTransGPS:(CLLocationCoordinate2D)yGps
{
 
    NSString *database_path = [[NSHomeDirectory() stringByAppendingString:@"/Documents/"] stringByAppendingString:DBNAME];
 
    if (sqlite3_open(database_path.UTF8String, &db) != SQLITE_OK) {
        sqlite3_close(db);
        NSLog(@"Open gps data failed!");
    }
 
    int TenLat=0;
    int TenLog=0;
    TenLat = (int)(yGps.latitude*10);
    TenLog = (int)(yGps.longitude*10);
    NSString *sql = [[NSString alloc]initWithFormat:@"select offLat,offLog from gpsT where lat=%d and log = %d",TenLat,TenLog];
    NSLog(@"SQL command:%@", sql);
    const char * sqlc= [sql UTF8String];
 
    sqlite3_stmt* stmtL ;
    if (sqlite3_prepare_v2(db, sqlc, -1, &stmtL, nil) != SQLITE_OK)
    {
        NSLog(@"SQl prepare failed %s",sqlite3_errmsg(db));
    }
 
    int offLat=0;
    int offLog=0;
    while (sqlite3_step(stmtL)==SQLITE_ROW)
    {
        offLat = sqlite3_column_int(stmtL, 0);
        offLog = sqlite3_column_int(stmtL, 1);
 
    }
 
    yGps.latitude = yGps.latitude+offLat*0.0001;
    yGps.longitude = yGps.longitude + offLog*0.0001;
    return yGps;
}
</sqlite3>